Q:

Consider the recursively defined function below.f(1)=-5.25f(n)=f(n-1)+1.75, for n=2,3,4,....Create the first five terms of the sequence defined by the given function.Tiles: [-7.5], [-1.5], [-1.75], [-5.25], [1.75], [-3.5], [0], [1.5]Sequence: ?

Accepted Solution

A:
Answer: Β  -5.25, -3.5, -1.75, 0, 1.75Step-by-step explanation:The recursive relation tells you this is an arithmetic sequence with a common difference of 1.75. Each term is 1.75 more than the one before.To find the 2nd term, add 1.75 to the first term: -5.25 + 1.75 = -3.5To find the 3rd term, add 1.75 to the second term: -3.5 + 1.75 = -1.75To find the 4th term, add 1.75 to the third term: -1.75 + 1.75 = 0and so on ...