Find the largest value of x that satisfies:log3(x^2)-log3(x+4)=4
Accepted Solution
A:
Answer:Step-by-step explanation:log3(x^2)-log3(x+4)=4Log 3(x^2/x+4)=4 -Combine the logsx^2/x+4 = 3^4 - Use the relationship Logb(y)=x =>b^x=yx^2/x+4 = 81x^2= 81^(x+4)x^2=81x+324x^2-81x-324=0Solving for x using the property x=-b-/+[tex]\sqrt{x} b^2-4ac]/ 2a=(81 ±√(81)^2-4^11^324)/2= (81±√6561-1296)/2=(81±88.63)/2= (81+88.63)/2=84.81