Q:

solve the system of equations y=-2x y=x2-8

Accepted Solution

A:
Answer: [tex]x=-4\\y=8\\\\x=2\\y=-4[/tex]Step-by-step explanation: Make both equations equal to each other and solve for x: [tex]-2x=x^2-8\\0=x^2+2x-8[/tex] Factor the quadratic equation. You need to find two number that when you add them you get 2 and when you multiply them you get -8. These numbers are 4 and -2. Then: [tex]0=(x+4)(x-2)\\\\x+4=0\\x=-4\\\\x-2=0\\x=2[/tex] Substitute the values of x calculated, into any of the original equations. Then: Β [tex]y=-2(-4)\\y=8\\\\y=-2(2)\\y=-4[/tex]